A simplified version of this expression would be something like:
1/2 + 1/3 = ?
To find the answer to this question you have to find the lowest common multiple. Here the answer is 6 (2*3), then do this:
[(1/2) * [(3/3)] = 3/6
+
[(1/3) * 2/2] = 2/6
= 5/6
The expression that you have is just a slightly more complex version of this...
The lowest common multiple is (y+5)(y-1)...
4y/(y+5) * (y-1)/(y-1)
= 4y^2 -4y /(y+5)(y-1)
+
2y/(y-1) * (y+5)/(y+5)
=2y^2+10y/(y+5)(y-1)
=6y^2+6y / (y+5)(y-1)
2006-09-20 16:26:11
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answer #1
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answered by mindful1 3
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First you have to combine the 2 terms
to do that you need get a common denominator
the numerator will look like this during the process
4y*(y-1) + 2y*(y+5) =
4y^2 - 4y + 2y^2 + 10y =
6y^2 +6y
The denominator is
(y-1)*(y+5)=
y^2 + 4y -5
so the answer is
(6y^2 +6y)/(y^2 +4y -5)
2006-09-20 23:07:32
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answer #2
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answered by tcarrw 3
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Give them common denominators:
4y(y-1) + 2y(y+5)
--------- ----------
(y-1)(y+5) (y-1)(y+5)
Now that they have the same denominators, you can add the numerators:
Factor to your liking
2006-09-20 23:00:53
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answer #3
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answered by Gordo J 2
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4y (y-1) + 2y (y+5)
------------------------- =
(y+5) (y-1)
2y^2 + 1
-----------
(y+5)(y+1)
you should be able to go from there. Good luck!
2006-09-20 23:07:05
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answer #4
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answered by scooby doo 3
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=4y(y-1)+2y(y+5)
=4y^2-4y+2y^2+10y
=6y^2+6y
=6y(y+1)
I think thats it...
2006-09-20 22:58:20
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answer #5
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answered by LameSkull 2
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common denominator...of y+5 and y-1so 4y(y-1) + 2y(y-5).....
4y^2-4y+ 2y^2-10y then combine like terms... 6y^2-14y
2006-09-20 23:03:20
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answer #6
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answered by who be boo? 5
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4y^2 + 20y + 2y^2 - 2y
Now simplify.
6y^2 + 18y
2006-09-20 22:57:53
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answer #7
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answered by Angelic Vampiress 2
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4y 2y
---- + ----
y+5 y-1
=
4y + 2y
----------
y+5+y-1
=
6y
-----
2y + 4
2006-09-20 23:02:40
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answer #8
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answered by gottaluvme 3
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If it is equal to 0 and / means divide, then you mulitiply the entire equation by (y+5)(y-1).
2006-09-20 22:56:38
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answer #9
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answered by stooperfrreeeek 1
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Distribute to the numbers in the parenthesis and simplify.
2006-09-20 22:56:26
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answer #10
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answered by Anonymous
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