(-3.35) to the exponent ^ -1.2?

Answer 1

You should use these formula's to make this problem easier for yourself. first: x^(-a) = 1/(x^a) so (-3.35) ^ (-1.2) = 1 / [(-3.35) ^ 1.2]
and you can change 1.2 to 6/5 (1.2=6/5).so 1 / [(-3.35) ^ 1.2] = 1 / [(-3.35) ^ (6/5)]
next: [(x^a)^b] = x^(a*b) so: 1 / [(-3.35) ^ (6/5)] = 1 / [((-3.35) ^ 6) ^ (1/5)] ≈ 1 / [1413.412 ^ (1/5)] ≈ 1 / 4.266 ≈ 0.234

Answer 2

(-3.35)^-1.2 = 1/(-3.35)^1.2 = 1/(-3.35)^(6/5)

this = 1/[(-3.35^1/5]^6 or, one over the fifth root of -3.35 raised to the sixth power. The fifth root of -3.35 is - 1.274; this to the sixth power is -4.276. 1/-4.276 = -.234

Answer 3

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in the wold of real numbers, the function a^x is defined for positive values of the base a and any real x.

try plug in your example into a calculator with a y^x build in function -- you will get an error.

Answer 4

.23439