I did a science lab where we took a constant velocity car and recorded its position every two seconds. I did the experiment in two parts of data, one going in a positive direction and the other in negative.
How do I determine the relationship between its position and its time?
2006-09-20 14:15:55 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Physics
d=vt+d_0
Where d=final displacement, v=velocity, t=time, and d_0=initial displacement
2006-09-20 14:21:19 · answer #1 · answered by Pascal 7 · 2⤊ 0⤋
You should plot your values in a graph. Your data points will form a line that starts in origin and has a slope. Measure this slope.
The equation for a line is.
distance=a*time+b
b=0 since the distance is 0 when the time is zero.
a=the slope in your plot=the speed
2006-09-20 21:26:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
As time increases the cars position will change in even increments in either a forward (positive) or backword (negative) motion.
2006-09-20 21:23:28 · answer #3 · answered by T F 3 · 0⤊ 0⤋
hopefully there directly proportional. except if your car were to travel really fast (say the speed of light) then time would start to slow down for that car. weird huh?
2006-09-21 01:08:02 · answer #4 · answered by strontium b 1 · 0⤊ 1⤋
x = v x t
the graph is a straight line not parallel to time axis
2006-09-20 22:44:28 · answer #5 · answered by Need Help 2 · 0⤊ 0⤋
this has to do nothing about the question what u said to me how mean i m not in it for just the poularity ok
2006-09-20 22:45:49 · answer #6 · answered by poojahere4u 2 · 0⤊ 1⤋