Ok, this might seem easy...but I really need the answer fast!!!
what is the limit of f(x) as x approaches 0 of sin^3(2X)/(X^3)?
2006-09-20 14:05:16 · 6 answers · asked by Aurora 1 in Science & Mathematics ➔ Mathematics
never mind, I got it. the answer's 8
2006-09-20 14:09:54 · update #1
Limit x -->0 sin^3(2x) / x^3
Split it up as follows
Limit [sin(2x)/x] * [sin(2x)/x] * [sin(2x)/x]
Limit of product is product of limits
Limit [sin(2x)/x] = 2 Limit sin(2x)/(2x) = 2
2*2*2 = 8
2006-09-20 14:27:18 · answer #1 · answered by z_o_r_r_o 6 · 1⤊ 0⤋
You can use L'Hopital's theorem here, since both the top and bottom resolve to 0 as you approach the limit (sin 0 = 0).
The actual solution is messy and might take a few steps to get there, so forgive me if I don't follow it all the way through.
2006-09-20 14:08:28 · answer #2 · answered by Neodiogenes 6 · 0⤊ 0⤋
as x tends to zero, the function tends to 0 aswell i think
2006-09-20 14:12:24 · answer #3 · answered by moin e 2 · 0⤊ 0⤋
LOL. Good that your got. I am not to sure if someone would have got the right answer.
2006-09-20 14:14:25 · answer #4 · answered by de_dark_angel71 3 · 0⤊ 0⤋
Why can people not do their own homework?
2006-09-20 14:08:03 · answer #5 · answered by kd5pzz 2 · 0⤊ 1⤋
can't u use a calculater don't know sorry
2006-09-20 14:07:16 · answer #6 · answered by Lion 1 · 0⤊ 1⤋