is it 15 or 120?? ... math isn't my stronghold
2006-09-20 13:20:42 · 8 answers · asked by david p-p-preut 1 in Science & Mathematics ➔ Mathematics
Luigi gave you the right answer, 120.
Imagine that you have 5 spaces, and you're going to place the 5 objects into those spaces.
There are 5 choices for the first space you fill.
then you have to choose one of the remaining 4 items for the second space.
So there are 20 different ways to fill those first two spaces (20 = 5 x 4).
Then there are 3 choices for the next space, and 2 for the one after that.
Finally, you have one space left to fill and one object to place into it, so there is only one choice.
Result: Total possible ways of doing it (called the number of arrangements, or "permutations") is 5x4x3x2x1 = 120
2006-09-20 13:26:30 · answer #1 · answered by actuator 5 · 0⤊ 0⤋
Well, lets take a looksee.
You have 5 objects, and 5 locations.
For the first location, you have 5 options.
After using that ovject, for space 2 you have 4 options for that one.
Then on space 3, 3 options.
Space 4, 2 options.
And space 5, the last object.
Mathmaticaly, the equation will be 5*4*3*2*1=120
Or, a factorial. 5!=120.
Regardless, the answer is 120 possabilites.
2006-09-20 20:26:34 · answer #2 · answered by zealot_guy 3 · 0⤊ 0⤋
1 combination - the order in which the objects are arranged does not make any difference.
Now, if you meant how many _permutations_ are there, then it's 5! or 120 permutations.
2006-09-20 20:25:28 · answer #3 · answered by Pascal 7 · 1⤊ 0⤋
5! or 5*4*3*2*1 or 120
2006-09-20 20:22:17 · answer #4 · answered by Luigi 3 · 0⤊ 0⤋
It would be 120 just like the first person said.
2006-09-20 20:27:14 · answer #5 · answered by Bryant 1 · 0⤊ 0⤋
it should be 25
2006-09-20 20:26:57 · answer #6 · answered by Nessa 2 · 0⤊ 0⤋
25?
2006-09-20 20:22:28 · answer #7 · answered by ABC 4 · 0⤊ 1⤋
5X5=25. 25 combo
2006-09-20 20:22:37 · answer #8 · answered by La Princesa 6 · 0⤊ 1⤋