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2006-09-20 13:05:19 · 8 answers · asked by jose h 2 in Science & Mathematics Mathematics

8 answers

First check that you copied the question correctly. There are 2 variables and only one equation. Usually this would not be the case if you want to obtain a unique answer.

So what you can do is solve for one of the variables in terms of the other. Solve for x

x = 7d - 27/2

Now assume some values for d (here we are taking some liberty as we do not know if in fact d can have the values we select)

This will give you a series of ordered pairs...plot these and see what you have found :-)

X d
0
2
4
-2
-4
-6


GOOD LUCK !!

2006-09-20 13:21:16 · answer #1 · answered by travlin 2 · 1 0

You have 1 equation with 2 unknowns (x and d).
When you have more unknowns than equations, there is not a single solution (except when it's an oddball equation).

Here, d can be any value you choose, and you can find a value of x that works with it. You could make a graph showing the relationship of x and d (it would be a straight line on the graph).

If you simplify the equation, you can convert it to:
x = 7 d -27/2
As mentioned, whatever value you choose for d, you can use this equation to find the corresponding value of x.
(Example: if d is 0, x is -27/2)

2006-09-20 20:12:01 · answer #2 · answered by actuator 5 · 0 0

2x + 34 = 14d + 8
2x = 14d -26
x = 7d - 13

now substitude the x

2(7d - 13) + 34= 14d + 8
14d + 8 = 14d + 8
d= 0

x= 7(0) -13
x= -13

2006-09-20 20:12:55 · answer #3 · answered by lakersforlife 3 · 1 0

it is 2x +42 -7 = 14d +8
so 2x = 14d - 27
So the solution is a line that pass by (0,-27/2) and (2, -1/2)

2006-09-20 20:09:12 · answer #4 · answered by fred 055 4 · 0 0

Okay chester isn't that cheating? You still have to get it to take the test. Don't sell yourself short and practice. With practice comes understanding. I just went through it. If you won't practice then you will never get it.

2006-09-20 20:14:41 · answer #5 · answered by Patriot 2 · 0 1

Can't be done; two different variables need at least 2 different equations

2006-09-20 20:07:51 · answer #6 · answered by hayharbr 7 · 1 0

r u solving 4 "x" or "d"?

2006-09-20 20:08:05 · answer #7 · answered by KaY 1 · 0 1

It's your homework,you do it

2006-09-20 20:07:05 · answer #8 · answered by Anonymous · 0 1

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