First check that you copied the question correctly. There are 2 variables and only one equation. Usually this would not be the case if you want to obtain a unique answer.
So what you can do is solve for one of the variables in terms of the other. Solve for x
x = 7d - 27/2
Now assume some values for d (here we are taking some liberty as we do not know if in fact d can have the values we select)
This will give you a series of ordered pairs...plot these and see what you have found :-)
X d
0
2
4
-2
-4
-6
GOOD LUCK !!
2006-09-20 13:21:16
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answer #1
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answered by travlin 2
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You have 1 equation with 2 unknowns (x and d).
When you have more unknowns than equations, there is not a single solution (except when it's an oddball equation).
Here, d can be any value you choose, and you can find a value of x that works with it. You could make a graph showing the relationship of x and d (it would be a straight line on the graph).
If you simplify the equation, you can convert it to:
x = 7 d -27/2
As mentioned, whatever value you choose for d, you can use this equation to find the corresponding value of x.
(Example: if d is 0, x is -27/2)
2006-09-20 20:12:01
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answer #2
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answered by actuator 5
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2x + 34 = 14d + 8
2x = 14d -26
x = 7d - 13
now substitude the x
2(7d - 13) + 34= 14d + 8
14d + 8 = 14d + 8
d= 0
x= 7(0) -13
x= -13
2006-09-20 20:12:55
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answer #3
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answered by lakersforlife 3
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it is 2x +42 -7 = 14d +8
so 2x = 14d - 27
So the solution is a line that pass by (0,-27/2) and (2, -1/2)
2006-09-20 20:09:12
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answer #4
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answered by fred 055 4
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Okay chester isn't that cheating? You still have to get it to take the test. Don't sell yourself short and practice. With practice comes understanding. I just went through it. If you won't practice then you will never get it.
2006-09-20 20:14:41
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answer #5
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answered by Patriot 2
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Can't be done; two different variables need at least 2 different equations
2006-09-20 20:07:51
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answer #6
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answered by hayharbr 7
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r u solving 4 "x" or "d"?
2006-09-20 20:08:05
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answer #7
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answered by KaY 1
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It's your homework,you do it
2006-09-20 20:07:05
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answer #8
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answered by Anonymous
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