Tickets for a benefit dinner were on sale for three weeks. During the third week, twice as many tickets sold as the first two weeks combined. If a total of 1095 tickets were sold, how many were sold the third week?
2006-09-20 12:15:00 · 7 answers · asked by ♥val♥ 1 in Education & Reference ➔ Homework Help
2190 it is simple math
2006-09-20 12:17:17 · answer #1 · answered by DevilHunter 2 · 0⤊ 0⤋
Let x = amount of tickets sold on the third week
Let y = amount of tickets sold on all other weeks
x + y = 1095 the amount of tickets sold the third week + the amount of tickets sold the first two weeks = the total amount of tickets sold
x = 2y "During the third week, twice as many tickets were sold as the first two weeks"
So now we just need to solve this system of equations:
x + y = 1095
x = 2y
Substitute 2y in for x in the first equation.
2y + y = 1095
3y + 1095
y = 365
x = 2y
x = 730
730 tickets were sold the third week.
2006-09-20 12:19:00 · answer #2 · answered by mattomynameo 4 · 1⤊ 0⤋
It's easy, take the total amount sold (1095) and divide by 3, and you get (365) then you subtract(365) from the total amount sold and you get the answer (730).the amount sold the third week.
2006-09-20 12:57:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If twice as many tickets were sold, shouldn't the answer be an even number?
2006-09-20 12:18:33 · answer #4 · answered by Bethany 7 · 0⤊ 0⤋
730 tickets
2006-09-20 12:22:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋
divide by four then multiply by two
2006-09-20 12:17:19 · answer #6 · answered by Pinxy 2 · 0⤊ 0⤋
You add what you've done and then I'll add the way it's done.
2006-09-20 12:19:31 · answer #7 · answered by madjer21755 5 · 0⤊ 0⤋