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4 answers

6 ways or six 3 digit nos without repetition using 6,7 and 8

2006-09-20 10:07:51 · answer #1 · answered by raj 7 · 0 0

There are 3 digits you can choose for the first place, leaving only 2 available for the second place, leaving just 1 for the last place. Thus, you have 3*2*1=6 possible permutations of 6,7,8 in a three digit number.

The six arrangements are:

678
687
768
786
867
876

2006-09-20 17:13:32 · answer #2 · answered by Ted 4 · 0 0

Since you have three choices (6, 7, and 8) for the numbers to use, it's a permutation solved by 3*2*1 = 6 different ways.

2006-09-20 17:09:34 · answer #3 · answered by jrobbins324 2 · 1 0

use a mirror and then count

2006-09-20 17:12:19 · answer #4 · answered by Anonymous · 0 0

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