would it be (x^2-0) (x^2+0) ?
thanks for your help.
2006-09-20 09:34:10 · 9 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
how do you find the zeros to x^4? would it be 0?
2006-09-20 09:45:17 · update #1
(x^2)(x^2) is definitely one of the ways, and since you could factor x^2 into (x)(x) then x^4 could also be (x)(x)(x)(x). Just depends on how far you want to factor it.
2006-09-20 09:38:54 · answer #1 · answered by jrobbins324 2 · 0⤊ 2⤋
X^4 is already as low as it can go, unless you consider x^2 * x^2 or X * X * X * X.
Since X^2 - or + 0 is the same as X^2, you are really just saying X^2 * X^2.
2006-09-20 16:39:13 · answer #2 · answered by Anonymous · 0⤊ 1⤋
x^4=0 has only 1 cero,
namely x=0, it is a cero of order 4
2006-09-20 17:04:10 · answer #3 · answered by locuaz 7 · 0⤊ 0⤋
x^4 = x * x * x * x
2006-09-20 16:39:48 · answer #4 · answered by Nancy F 2 · 0⤊ 1⤋
well x^4 is only factorable if you really want to factor it
x * x * x * x
also can be written like
x*x^3
x*x*x^2
x^2*x^2
but usually you dont factor x^4 because it is already self explanatory just x times itself four times!
2006-09-20 16:39:27 · answer #5 · answered by nate 3 · 0⤊ 1⤋
It has four factors: x, x, x, and x
Are you sure this is the question you wanted to ask?
2006-09-20 16:38:59 · answer #6 · answered by kindricko 7 · 0⤊ 1⤋
it would be x times x times x times x.
at least i think it would be.
2006-09-20 16:39:48 · answer #7 · answered by mj 2 · 0⤊ 1⤋
(x)(x)(x)(x)
2006-09-20 17:39:25 · answer #8 · answered by Anonymous · 0⤊ 0⤋
It would be (x)(x)(x)(x).
QED
2006-09-20 16:55:04 · answer #9 · answered by CSUFGrad2006 5 · 0⤊ 1⤋