Can you please explain how to do this problem?

Question

Write the equation (in point-slope form and slope-intercept form) of a line parallel to 2x - 5y=10 and goes thru point (-5,2)

please go thru the problem step by step

Answer 1

y=mx + b

y= -2/5 + 5

y = -2/5x + 2 << is your answer I THINK in point slope

Answer 2

Point-slope form is y - y1 = m(x - x1) where m is slope and x1 and y1 are the coordinates in an ordered pair.
Slope-intercept form is y = mx + b where b is the y-intercept.

Solve your equation for y to find the slope.
2x - 5y = 10
-5y = -2x + 10 Now divide each term by -5.
y = 2/5 x - 2. This is the slope-intercept form of your original equation. The slope you want is the coefficient of x, so it's 2/5.

Use point-slope form to find the equation you want. Parallel lines have the same slope. Substitute -5 for x1 and 2 for y1.

y - 2 = 2/5(x +5)

Answer 3

slope intercept form
First convert the equation to slop intercept form
1. 2x-5y=10
2. -5y=10-2x
3. y=2-(2/5)x
4. y=-(2/5)x+2
a parallel line will have the same slope (-(2/5))

Point-Slope is going to be y-y1=slope(x-x1)
y-2=((-2/5))(x+5)

Slope Intercept of this equation is
y=(-2/5)X

Answer 4

putting equation 2x-5y=10 in y=mx+c form we get -5y= -2x+10
y=2/5x-2
slope of this equation=2/5
therefore slope of line parralel to this line is 2/5
we know equation of a line passing through a poin(x1,y1) havin a slope m is
y-y1=m(x-x1)
y-2=2/5{x-(-5)}
y-2=2/5(x+5)
5y-10=2x+10
2x-5y= -20

Answer 5

2x-5y=10
-5y=-2x+10
y=(2/5)x-2
slope=2/5
slope of the reqd. line=2/5
passes through (-5,2)
equation=y-2=(2/5)(x+5)
5y-10=2x+10
2x-5y+20=0