factoring completely with work
2006-09-20 07:57:28 · 6 answers · asked by spanishfly_100 1 in Education & Reference ➔ Homework Help
8x^2 - 2y^2
1.) Split out the 2.
2 (4x^2 - y^2)
2.) When you have x^2 - a^2, the factors are (x+a) (x-a).
Thus: (4x^2 - y^2) = (2x + y) (2x-y)
Final factors : 2 (2x + y) (2x-y) (solution!)
Check:
2 (2x + y) (2x-y)
2 (4x^2 + 2xy - 2xy - y^2)
2 (4x^2 - y^2)
8x^2 - 2y^2 (check!)
2006-09-20 08:03:05 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
8x^2 - 2y^2
2(4x^2 -y^2)
= 2(2x-y)(2x+y)
2006-09-20 15:13:09 · answer #2 · answered by Superconductor 3 · 0⤊ 0⤋
Good lord, man - ask your teacher for help, or at least let her know that you didn't know how to do this basic factoring equation so you resorted to letting complete strangers on the internet do it for you.
2006-09-20 15:05:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
= 2(4x^2 - y^2) = 2(2x - y)(2x + y)
2006-09-20 15:01:58 · answer #4 · answered by steven o 2 · 0⤊ 0⤋
2(4x^2-y^2)=2(2x+y)(2x-y)
2006-09-20 15:00:05 · answer #5 · answered by raj 7 · 0⤊ 0⤋
2(4x^2-y^2).....2(2x+y)(2x-y)
2006-09-20 15:02:04 · answer #6 · answered by who be boo? 5 · 0⤊ 0⤋