Chem question C,H,O, S?

Question

An organic compound containing C,H,O,and S is subjected to two analyitcal procedures. In the first procedure a 9.33 mg sample is burned which gives 19.5 mg of CO2 and 3.99 mg of H2O. IN the second procedure, a seperate 11.05 mg sample is fused (melted) with Na2O2 and the resulting sulfate is precipitated as BaSO4, which (when dried) weighs 20.4 mg( Appropriate amounts of Na2O2 and a compound containing barium ion are added.) The amount of oxegen in the original sample is obtained by difference. Determain the empirical formula of this compound.)

Answer 1

Set up simultaneous equations relating all of the source data, and let the variables be the moles of C, H, O, and S. These equations would be:
12C+H+16O+32S = 9.33
12C = 19.5/(12+16+16)
H = 3.99/(1+1+16)
32S = 20.4/(137+32+64)
16O = 9.33 - 12C - 32S - H
Then you break out your four-banger and get to work. Once you have the number of moles of each element, you divide the smallest number into each of the other three to get the atom counts. If the atom counts turn out to be rational fractions, multiply everything by the reciprocal of the smallest denominator to turn everything into integers.

Take the time to figure out where each of these equations came from. It isn't difficult.

Answer 2

Thank you Mr. Saunders for not doing all the work for his student. It makes me think you are a very good teacher.