Ok the equation was: Seven more than twice a given number is 21. Find the number. I put 7+x=21 and subtracted 7 from each side but got it wrong, HELP!
2006-09-20 06:46:42 · 7 answers · asked by dahamu_626 1 in Education & Reference ➔ Homework Help
7 + (2x) = 21 (remember it says twice a given number!)
2x = 14
x = 7
check: 7 + (2*7) = 21
7 + 14 = 21...!! tada! :)
2006-09-20 06:49:44 · answer #1 · answered by sasmallworld 6 · 0⤊ 0⤋
7 more than TWICE the given number. The given number is x. Therefore, twice the given number is 2x. After that, since it says that 21 is seven more than twice the number, add 7 to 2x. The equation is 2x + 7 = 21.
Subtract 7 from both sides and you get 2x = 14.
Divide each side by two and you get x = 7.
2006-09-20 14:04:24 · answer #2 · answered by l;wksjf;aslkd 3 · 0⤊ 0⤋
Lets put down the numbers first (you forgot the twice a given number part)
7+2x=21 (subtract 7 from each side)
2x=14 (divide by 2)
x=7
2006-09-20 13:50:06 · answer #3 · answered by Robin A. 3 · 0⤊ 0⤋
Let the number be x, then according to question
2x+7=21(twice the given number means 2x)
2x=21-7
2x=14
x=14/2
x=7
2006-09-20 13:57:01 · answer #4 · answered by flori 4 · 0⤊ 0⤋
twice the given number. The given number is x therefore it should be 2x
7 + 2x = 21
2006-09-20 13:49:17 · answer #5 · answered by gingersnapgrad2003 2 · 0⤊ 0⤋
7+2x=21
2x=14
x=7
2006-09-20 13:51:36 · answer #6 · answered by raj 7 · 0⤊ 0⤋
No
2006-09-20 13:53:47 · answer #7 · answered by NONAME 1 · 0⤊ 0⤋