2006-09-20 06:21:55 · 6 answers · asked by Elizabeth 1 in Science & Mathematics ➔ Mathematics
Please sho your work as fully as possible
2006-09-20 06:22:47 · update #1
First you find the floor area by 800x10x10 = 80000 cm^2. Then find area of new tile 8x8 = 64 cm^2. We need 80000/64 = 1250 tiles.
Why did I get a thumbs down? The answer is correct.
2006-09-20 06:27:20 · answer #1 · answered by Anonymous · 3⤊ 1⤋
Given that the floor is covered with tiles measuring 10sq. cm.
No. of tiles presently covering the floor = 800
Therefore, total area of the floor = 800 X 10 sq. cm.
= 8000 sq. cm.
Now, when tiles of side measuring 8 cm are to be used,
area of one such tile = side * side
= 8 * 8 sq. cm.
= 64 sq.cm
Thus, number of tiles of side 8cm needed to cover the floor is given by the formula (Area of floor)/(Area of one tile)
= 8000/64
=125
Therefore 125 square tiles of side 8 cm will be needed.
2006-09-20 06:34:05 · answer #2 · answered by noesis 2 · 0⤊ 0⤋
800 tiles x 100 sq cm/tile = 80000 sq cm; using 10 x 10 tile.
80,000 / 64 sq cm/tile = 1250 8x8 tiles.
2006-09-20 06:31:48 · answer #3 · answered by lil'oleJewler 2 · 0⤊ 1⤋
Aquick guess says 1000 tiles.
2006-09-20 06:30:42 · answer #4 · answered by old man 2 · 0⤊ 0⤋
You tell us
2006-09-20 06:23:58 · answer #5 · answered by Anonymous · 0⤊ 0⤋
pick dude's answer. that's the answer.
2006-09-20 06:36:48 · answer #6 · answered by Masyaw 2 · 0⤊ 0⤋