Algebra, not good with word problems...please and thanks?

Question

39.
Janet invested $25,000, part at 5% and part at 2%. If the total interest at the end of the year is $980, how much did she invest at 5%?

A) $16,000 B) $9,000 C) $15,000 D) $17,000

Answer 1

If her return at the end of the year was 980$ then her average rate of return was: 980/25000=3.92%.
X*5+(1-X)*2=3.92
3X=1.92
X=.64
Therefore, Janet invested 16000 at the 5% rate: A

Answer 2

Since this is a multiple answer type question, I would suggest that you not try to solve for the solution algebraically but go with trial and error like so :
take option A , $16000 @ 5% =$800
The remainder $9000 @ 2% = $180
therefore total 800 +180 =980, hence true.

Answer 3

To solve this problem:

1. What percentage of 25,000 is 980?
2. How would you weight 2% and 5% to come up with the percentage you get in (1)?
3. Take the weight you calculate for 5%, and multiply that by 25,000. That's your answer.

Answer 4

Interest = principal times rate

980 = .05x + .02y
980 in interest equals 5% times the amount invested x + 2% times the amount invested y

x + y = 25000
amount invested at 5% plus the amount invested at 2% equals the total amount we had to invest. 25000

Solve the two equations using either elimination or substitution.

Hope this helps. Good Luck.

Answer 5

ler x = amount at 5%, then 25000-x is amount at 2%

.05x+.02(25000-x) = 980

solve for x .05x+500-.02x=980
.03x=480
3x=48000
x=16000