For some reason I can not come up with this answer can someone help.
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft2. What must be the width of the walkway to the nearest thousandth?
A) 5.430 ft B) 3.860 ft C) 2.610 ft D) 7.720 ft
2006-09-20 02:02:57 · 3 answers · asked by BlueEyes4172004 1 in Science & Mathematics ➔ Mathematics
Let the width of the walkway = x.
So (30+2x)(40+2x)=1800
=>4x^2+140x-600=0
x = 3.860
2006-09-20 02:08:05 · answer #1 · answered by astrokid 4 · 0⤊ 0⤋
Let the width of the path be x ft
:
Total area (30+2x)(40+2x) = 1800
Multiply 1200 + 60x + 80x +4x^2 = 1800
4x^2 + 140x - 600 = 0
Solve, x = 3.86 ft
2006-09-20 10:10:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
B) 3.86
2006-09-20 09:12:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋