sin x over 2n = 3
2006-09-20 00:57:13 · 7 answers · asked by gonpatrick21 3 in Science & Mathematics ➔ Mathematics
hahahaha....... k i think i got it...
sin x/ 2n
cancel off the n...
= six/2
= 3
LOL...
good one !!!
2006-09-20 01:00:56 · answer #1 · answered by Nirmal87 2 · 0⤊ 1⤋
This is a classic example of how idiots try to bend the beauty of mathematics to their incompetant will.
Their "argument" is that the "n" of the sine funtion cancels off with the n in the denominator
i.e
[sin x] / 2n = si x / 2 =6/2 =3
2006-09-20 01:43:34 · answer #2 · answered by yasiru89 6 · 1⤊ 0⤋
This is not correct but if u insist then
(sin x)/(2n) = (six)/(2) {by cancelling out the n}
= 3
again I must point out that this is not the way to do maths.
2006-09-20 01:23:14 · answer #3 · answered by Prof K 2 · 0⤊ 0⤋
does your
sin x = sin (x) and 2n = 2*n
then
sin (x)/2n cannot equal to 3 everytime. but can be equal to 3
under certain values for x and n.
2006-09-20 01:51:42 · answer #4 · answered by tronic_hobbist 2 · 0⤊ 0⤋
If u meant sinx/2n =3 then
'n' gets cancelled between numerator and denominator leaving six/2
This will give the result 3
2006-09-20 01:04:20 · answer #5 · answered by rags 2 · 0⤊ 1⤋
It cannot be proved because it is not true -- for any parenthesization.
2006-09-20 01:13:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I don't get it
2006-09-20 01:15:27 · answer #7 · answered by Anonymous · 0⤊ 0⤋