some creative answers:
(1) he catches the express train, not the stopping train
(2) he swops the mangoes for some other fruit before he sets out and is not then bound by the condition he agreed to
(3) he eats all the magoes before he gets on the train
(4) he puts all the mangoes in the guards van and has no mangoes about his person to disburse.
(5) He asks fellow passengers to say the mangoes are theirs, and give them back to him when he reaches his destination,
(6) he gets rid of the sacks and puts the mangoes in the luggage racks and phones his wife on his mobile phone to meet him at the station with two new sacks with which to take them home.
2006-09-19 20:24:48
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answer #1
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answered by Anonymous
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2 sacks of 100 mangoes = 200 mangoes. One way the man can have any left is to put all the mangoes in one sack. He then pays 1 mango at each station, and has 100 left over for himself. Another way is as suggested above, pay all fares out of 1 sack, having 50 left, assuming that all the mangoes will not fit in one sack.
2006-09-20 03:21:17
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answer #2
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answered by Helmut 7
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He has 2 sacks with 200 mangoes totally.
He gives the mangoes from one sack only. That way once he reaches the 50th station, he would have emptied out the first sack (given all 100 mangoes from it). Then, for the remaining 50 stations he has to give only 50 mangoes, ending up with 50 for himself!
nice one!! :)
2006-09-20 03:17:04
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answer #3
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answered by Unchained 2
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As soon as you can fit all the mangos into one sack, do it.
Then you only have to pay 1 mango per stop thereafter.
The sacks do hold at least 100 mangos, maybe more.
So after stop number 50, you should have 100 mangos total remaining. Discard the other sack and load all into 1.
50 more stops = 50 more mangos.
50 mangos left over for you.
Maybe more if the sacks hold more than 100 mangos.
2006-09-20 03:16:06
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answer #4
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answered by westmassboy76 1
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stands to reason 200 mangoes at 2 mangoes per station and 100 stations no mangoes will be left unless he gets rid of the sacks that he brings into the stations is this a trick question?
2006-09-20 03:20:02
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answer #5
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answered by dogpatch USA 7
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If he can, he should do away with sacks altogether and use a net instead for example, so he has no obligation to give mangoes. If this is cheating he has to put his 200 mangoes in 1 sack and give 100 away to get home so he is left with 100 mangoes.
2006-09-20 03:20:01
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answer #6
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answered by Sjors d 2
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Good question dude.
Solution. For the first 50 stations he hands over 2 mangoes to the Station master, takingthem out from the same sack. Thus at the end of 50 stations he has finished one sack. Now he puts this empty sack away. thus for the remaining 50 stations he gives only 1 mango per station, since he has only one sak. Thus on reaching his destination he still has 50 mangoes for himself.
I deserve my 10 points. Please give them to me
2006-09-20 03:43:50
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answer #7
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answered by cooldude 3
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Okay,ek "bharatiya" question.. so
for the first 50 stations,he'll give two mangoes each that will amount to a total of 100.Then he will have only ONE sack left with 100 mangoes for the next 50 stations.so he will have to give only 1 each for ONE SACK amounting to 50.That way,he'll have 50 left to take home.
2006-09-20 03:21:19
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answer #8
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answered by <akshun'k 4
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At the first fifty stations , he gives away two mangoes ( ie one per sack). He then transfers the remaing fifty from one sack to the other ( and throws away the empty sack). For the next fifty stations he gives out only one mango per stop and romps home with fifty.
2006-09-20 03:25:43
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answer #9
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answered by Rajesh Kochhar 6
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He should put all the mangoes in one large sack, at the end of journey he would still have 100 mangoes.
Or he could put them in basket (or something), and he would have 200 mangoes at the end.
2006-09-20 03:17:45
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answer #10
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answered by dragonfly140 3
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