i don't know how to show fractions on here so bare with me* 5 over y-4 minus 8 over y-4 = 2 over y^2-16-----i got -14 over 3 what would everyone else come up with? if i did it wrong i caould probably figure out where if i knew i had did it wrong--haha
2006-09-19 17:03:38 · 4 answers · asked by biznitchil 4 in Science & Mathematics ➔ Mathematics
5/(y-4) - 8/(y-4) = 2/(y^2-16)
5-8 = 2/(y+4) = -3
y = -2/3-4 = -14/3
you are correct!!
2006-09-19 17:14:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
5/(y-4) - 8/(y-4) = 2/(y^2-16)
(Are you sure one of the two denominators at the left is not y+4 instead?)
Multiply each fraction with y^2 - 16. Because y^2 - 16 = (y - 4) (y + 4) we get
5 (y+4) - 8 (y + 4) = 2
-3 (y + 4) = 2
y + 4 = -2/3
y = -4 2/3 = -14/3
So you should have done it right :)
2006-09-20 00:16:21 · answer #2 · answered by dutch_prof 4 · 0⤊ 0⤋
according to my math, in which i did by paper and pen, the answer is 14/3 and you are definitely correct.
2006-09-20 00:23:02 · answer #3 · answered by soar_2307 7 · 0⤊ 0⤋
yr RIGHT genius so am i
2006-09-20 01:56:08 · answer #4 · answered by Timothy B 2 · 0⤊ 0⤋