the base of a rectanglular vessel measures 10cm*18cm.water poured into a depth of 4cm. what is the pressure on the base?what is the force on the base?
2006-09-19 16:19:04 · 2 answers · asked by queenie 2 in Science & Mathematics ➔ Physics
The area is 10 cm x 18 cm = 180 cm2.
The volume is 180 cm2 x 4 cm = 720 cm3, or 720 mL = 0.720 L.
The mass of the water depends on the density, 1.00 kg / L, so the mass is 0.720 kg.
The force on the base is the weight of the water; using gravitational constant of g = 10 m/s2, you find weight to be 0.720 x 10 = 7.2 N.
The pressure is force divided by area, so we have 7.2 N / 180 cm2 = 0.04 N/cm2, or 400 Pa if you will.
The pressure is in fact independent of the area, and given by
p = g h rho
with h the height, rho the density; here,
p = 10 m/s2 * 0.04 m * 1000 kg/m3 = 400 Pa.
2006-09-19 17:04:04 · answer #1 · answered by dutch_prof 4 · 1⤊ 0⤋
I would think that the pressure on the base is the water and the force is gravity.
2006-09-19 23:21:03 · answer #2 · answered by Tiffany 4 · 0⤊ 0⤋