please help with both of these
Solve. 4(x + 2) – 3x = x – 6
and
Solve. 8x – 5 + 9x = 17x – 5
2006-09-19 16:11:46 · 5 answers · asked by jazminda S 1 in Education & Reference ➔ Higher Education (University +)
4(x+2)-3x=x-6
4x+8-3x=x-6
x+8=x-6
x+14=x inconclusive
8x-5+9x=17x-5
17x-5=17x-5
x is conclusive
2006-09-19 16:17:37 · answer #1 · answered by Mitchell B 4 · 0⤊ 1⤋
That's easy.
4(x + 2) - 3x = x - 6
4x + 8 - 3x = x - 6
4x + 8 - 3x - x + 6 = 0
0x + 14 = 0
0x = - 14
Note: No answer to this.
And
8x - 5 + 9x = 17x - 5
8x - 5 + 9x -17x + 5 = 0
8x - 8x (after 9x - 17x) - 5 + 5 = 0
0x + 0 (after - 5 + 5) = 0
0 = 0
Note: Regardless of whether x has any value, the formula will still lead the answer to 0.
2006-09-19 16:24:07 · answer #2 · answered by Anonymous · 1⤊ 0⤋
4x+8-3x=x-6
x+8=x-6
x-x=14
0=14(no solution because zero doesn't have a variable)
8x-5+9x=17x-5
17x-5=17x-5
0=0
2006-09-19 16:28:42 · answer #3 · answered by iwannarevolt 4 · 0⤊ 0⤋
4x+8-3x=x-6
x+8=x-6
x=x-14
no solution
8x-5+9x=17x-5
17x-5=17x-5
all real numbers
2006-09-19 16:21:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x=2 duhh
2006-09-19 16:13:52 · answer #5 · answered by Anonymous · 0⤊ 1⤋