Solve J(h(-3)) if j(X)= -2x + 7 and h(x)=5x2(squared)-2X
2006-09-19 14:43:18 · 5 answers · asked by Shirley B 1 in Science & Mathematics ➔ Mathematics
j(x) = -2x + 7
h(x) = 5x^2 - 2x
h(-3) = 5(-3)^2 - 2(-3) = 5(9) + 6 = 45 + 6 = 51
j(h(-3)) = j(51) = -2(51) + 7 = -102 + 7 = -95
j(h(-3)) = -95
2006-09-19 14:48:40 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
Just take your time with these problems...
J(h(-3))
h(-3) = 5(-3)^2 - 2(-3)
h(-3) = 45 + 6
h(-3) = 51
J(51) = -2(51) + 7
J(51) = -102+ 7
J(51) = -95
2006-09-19 21:48:45 · answer #2 · answered by alrivera_1 4 · 0⤊ 0⤋
h(-3) = 5(-3)^2 - 2(-3)
h(-3) = 45 + 6
h(-3) = 51
J(51) = -2(51) + 7
J(51) = -102+ 7
J(51) = -95
have fun with this
2006-09-20 02:13:31 · answer #3 · answered by Timothy B 2 · 0⤊ 0⤋
h(-3) = 5(-3)^2 - 2(-3)
h(-3) = 45 + 6
h(-3) = 51
J(51) = -2(51) + 7
J(51) = -102+ 7
J(51) = -95
good luck
2006-09-19 22:06:48 · answer #4 · answered by pearl 2 · 0⤊ 0⤋
first plug in -3 to h(x) then plug in that answer to j(x)
2006-09-19 21:46:20 · answer #5 · answered by bandido 4 · 0⤊ 0⤋