How do I simplify this: 2x^-2y^0(x^2y^0 - 4x^-6y^3)?

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How do I simplify this: 2x^-2y^0(x^2y^0 - 4x^-6y^3)?

2006-09-19 14:38:27 · 4 answers · asked by Tonya S 1 in Science & Mathematics ➔ Mathematics

4 answers

the way you wrote it is a little confusing, but just remember that anything to the power zero equals 1.

2006-09-19 14:46:51 · answer #1 · answered by banjuja58 4 · 0⤊ 0⤋

(2x^-2y^0)(x^2y^0 - 4x^-6y^3)

((2 * 1) * x^(-2 + 2) * y^(0 - 0)) + ((2 * -4) * x^(-2 + (-6)) * y^(0 + 3))

2x^(0)y^(0) - 8x^(-8) * y^3

ANS : 2 - ((8y^3)/(x^8)) or 2 - 8x^(-8)y^3

2006-09-19 21:56:31 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋

ok here the answer but i'm not sure
2x^2-2(x^2-4x^6y^3)
and the answer is :
-8x^6y^3

2006-09-19 21:52:48 · answer #3 · answered by pearl 2 · 0⤊ 0⤋

$1.98

2006-09-19 21:45:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋