2006-09-19 14:15:04 · 7 answers · asked by James M 1 in Science & Mathematics ➔ Mathematics
Consecutive even numbers a + (a+2)
a + (a+2 ) = 654
2a = 652
a = 326
So, numbers are 326 328
2006-09-19 14:21:13 · answer #1 · answered by alrivera_1 4 · 2⤊ 1⤋
First, split 600 in two, so the first digit will be 3. Then take 54 and halve it to get 27. Since we need two consecutive even numbers, look to subtract 1 from 27 = 26; add the 1 to 27 and get 28, put the 3 back on and we have 326 and 328.
2006-09-19 21:42:04 · answer #2 · answered by flyfisher_20750 3 · 0⤊ 1⤋
An easier way to get the answer is:
If the first room is room x, then the second room is (x+2). So, x + (x + 2 ) = 654 So, 2x = 652, hence x = 326 and (x + 2) = 328.
2006-09-19 21:26:34 · answer #3 · answered by Anonymous · 0⤊ 1⤋
x + x + 2 = 654; Combine like terms and solve for x (your first room) & then add 2 to it get the second room. e.g. 2x +2 = 654; 2x = 652; x=326 (and the second room is 328)
2006-09-19 21:21:13 · answer #4 · answered by Anonymous · 0⤊ 1⤋
326 328
2006-09-19 21:18:16 · answer #5 · answered by Roger 4 · 1⤊ 1⤋
x + (x + 2) + 654
x + x + 2 = 654
2x + 2 = 654
2x = 652
x = 326
ANS : Class 326 and 328
2006-09-19 21:58:40 · answer #6 · answered by Sherman81 6 · 0⤊ 1⤋
Simultaneous Equation
a+b=654 ---- (1)
a-b=2 ---- (2)
add (1) & (2)
2a=656 ---- (3)
div by 2
a=328 ---- (4)
into (2)
328-b = 2
b=326
a=328
b=326
Enjoy.
2006-09-19 21:20:07 · answer #7 · answered by S h ä r k G û m b ò 6 · 0⤊ 1⤋