i need some answers on my 8th grade honors algebra homework
2006-09-19 13:47:31 · 8 answers · asked by russel_gario 2 in Education & Reference ➔ Homework Help
6T+3=2T+11
4T=8
T=2
2006-09-19 13:49:56 · answer #1 · answered by raj 7 · 0⤊ 0⤋
t=2
2006-09-19 20:49:11 · answer #2 · answered by Scout Finch 2 · 0⤊ 0⤋
6t+3=2t+11
get the numbers on one side and the variables on the other
6t-2t=11-3
4t=8
then divide by the coefficient
t=2
2006-09-19 20:51:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The short answer is 2. but it is not such a hard problem.
6T+3=2T+11
so first you subtract 2T from both sides
4T+3= 11
then you subtract 3 from both sides
4T=8
then you divide both sides by 4
T=2
presto!
hope this helped
2006-09-19 20:50:42 · answer #4 · answered by homersdohnut 2 · 0⤊ 0⤋
6T+3= 2T+11
6T=2T+11-3
6T=2T+8
6T-2T=8
4T=8
T=8/4
T=2
2006-09-19 20:53:12 · answer #5 · answered by moosa 5 · 0⤊ 0⤋
6t+3=2t+ll
4t=8
t=2
2006-09-19 20:51:30 · answer #6 · answered by Anonymous · 0⤊ 0⤋
T=4, oops, forgot to carry the 1
2006-09-19 20:59:52 · answer #7 · answered by Ne'rDoWell 1 · 0⤊ 0⤋
6t + 3 = 2t + 11
-3 -3
---------------------
6t = 2t + 8
-2t -2t
---------------
4t= 8
t= 2
2006-09-19 20:51:11 · answer #8 · answered by Anonymous · 0⤊ 0⤋