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tell me how you did it

2006-09-19 13:22:03 · 9 answers · asked by DiaBEEtus 3 in Education & Reference Homework Help

9 answers

I agree with the t=5 people.

2006-09-19 13:27:16 · answer #1 · answered by asueb77 3 · 0 0

7(t - 5) = ?

To get rid of the paranthesis, you have to multiply the 7 by the t and the -5:

7 * t + 7 * -5 = ?

7t + -35 = ?

If you have a plus and a minus, you switch the sign to a minus:

7t - 35 = ?

Add the 35 to the other side, so you can even it out.

7t = 35

Divide by seven.

t = 5

Good luck! :)

2006-09-19 20:25:29 · answer #2 · answered by ? 2 · 0 0

First thing to do is Distribute
7(t-5)= 7t-35
So 7t-35=0
Add 35
So 7t=35
Then Divide both sides by 7
t=5
Now go back to the original equation:
7(t-5)
plug in t, which equals 5
7(5-5)
7(0)
0

2006-09-19 20:27:11 · answer #3 · answered by B-B@!! P!@Y@ 4 · 0 0

7(t-5) = 7t-35 (distribute the 7)

7t-35=0
+35 +35 (add 35 to each side)

7t=35
/7 /7 (divide each side by 7)

Answer t= 5

2006-09-19 20:26:27 · answer #4 · answered by a_rowe2004 2 · 0 0

7( t - 5) = first you go from left to the right by multiplying
7t - 35 = than you bring 35 to the right by equalling out to zero on both sites
+ 35 =
7t = 35 than divide by 7 to get t
t= 0.2

2006-09-19 20:25:26 · answer #5 · answered by angelikabertrand64 5 · 0 0

Umm... I don't think it's solvable unless you know t.
If you do know t, say for example you know t=6, then you would plug 6 in for t in the equation like so, 7(6-5)=? Then you go from inside the parentheses out solving the problem. 6-5 =1, right?
Now you have 7(1). That means multiply. So, 7*1=7

2006-09-19 20:25:10 · answer #6 · answered by jimboradley 2 · 1 0

distribute the 7--- 7*t and 7*-5
your answer is 7t-35

2006-09-19 20:24:44 · answer #7 · answered by thatshowiroll 3 · 1 0

If this is the exact question... then answer is 7t-35
using distributive property i.e a(b+c) = a*b + a*c

2006-09-19 20:24:35 · answer #8 · answered by Kartik 2 · 1 0

7t-(7*5)=0
7t-35=0
75=35
t=5

2006-09-19 20:26:20 · answer #9 · answered by sathya m 1 · 0 0

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