No one is home to tell me how to do this!
Mary and Jim have tickets to a concert. Mary's ticket # is 1 less then Jim's. The product of their #s is 812. What are the two numbers?
Would the algerbra aquation for this be:
'x' times 'x' minus 3 equals 812??????
And if yes, then how do I solve that? If no, what do I do??????? I'm so confused!
2006-09-19 12:18:39 · 9 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Let's call Mary's ticket number m and Jim's ticket number j.
"Mary's ticket # is 1 less then Jim's."
Mary's ticket -> m
is -> =
1 less than Jim's -> This is a bit more complicated.
1 is one less than 2,
2 is one less then 3...that's the pattern!
one less than 2 -> 2 -1
one less than 3 -> 3 -1
one less than Jim's number -> j -1
So, the math way of saying "Mary's ticket # is 1 less then Jim's" is:
m = j -1
A product is what you get when you multiply two numbers. Therefore, "The product of their #s is 812." means:
m * j = 812.
Since m = j - 1, I can make a substitution:
(j - 1) * j = 812
Can you solve the rest after his point?
2006-09-19 12:27:06 · answer #1 · answered by yetanotheronlinename 2 · 1⤊ 2⤋
X^2-3=812 so it means X squared minus 3 equals 812 you add 3 so you would have left x^2=815 so then get the square root which equals 28.5
2006-09-19 12:24:00 · answer #2 · answered by fernie201320 2 · 0⤊ 3⤋
x (x - 1) = 812
x^2 - x = 812
x^2 - x - 812 = 0
We now have a quadratic equation.
Using the quadratic formula:
x = (-b +/- sq. root of (b^2 - 4ac)) / 2a
x = (1 +/- sq. root of (1 - 4 * -812) / 2
x = (1 +/- sq. root of 3249) / 2
x = (1 +/- 57) / 2
x = 58 / 2 and x = 56 / 2
x = 29 and x = 28
2006-09-19 12:37:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x*(x-1)=812
x^2-x-812=0 solve this
29 and 28 are your answers
2006-09-19 12:28:57 · answer #4 · answered by bruinfan 7 · 2⤊ 0⤋
x(x)-3=812
whaat you do is work backwards.
first subtract 3 frm. 812=809
then since x(x)=Xto the 2nd power you find the square root of 809
2006-09-19 12:29:28 · answer #5 · answered by xoitfa 1 · 0⤊ 1⤋
let M's tkt be x
J's tkt=x+1
x(x+1)=812
x^2+x-812=0
(x+29)(x-28)=0
x=28
so mary's tkt is $28 and Jim's $29
2006-09-19 12:24:51 · answer #6 · answered by raj 7 · 3⤊ 0⤋
Easiest way:
Set Mary's ticket = M
Set Jim's ticket = J
MJ = 812
Mary's ticket is defined as J - 1
Therefore: M = J -1 (sub that into the equation)
J(J - 1) = 812
Once you get a value for J, sub that into the equation M = J - 1 to get Mary's ticket number.
2006-09-19 12:21:27 · answer #7 · answered by Manny 6 · 1⤊ 3⤋
no that's not the equation.
just use guess and try method.
the answer is:
Mary's #28
Jim's #29
28=1<29
28*29=812
2006-09-19 12:32:46 · answer #8 · answered by bcuster05 2 · 0⤊ 2⤋
Yeah, I kind of somewhat understand math but I don't know this. Sorry!
2006-09-19 12:21:12 · answer #9 · answered by Anonymous · 0⤊ 4⤋