2006-09-19 07:44:30 · 4 answers · asked by mrkitties420 4 in Science & Mathematics ➔ Mathematics
Go here for the various types of fractions you might encounter:
http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html
2006-09-19 11:18:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
after resolving into partial fractions use standard integrals to integrate
for example
(2x+3)/(x^2+3x+2) when resolved into partial fractions will be
1/(x+1) + 1/(x+2)
integral (2x+3)/(x^2+3x+2)=integral[1/(x+1) +1/(x+2)]
=ln(x+1)+ln(x+2)+C=>ln(x^2+3x+2)+C
2006-09-19 08:46:58 · answer #2 · answered by raj 7 · 0⤊ 0⤋
Because in certain cases there are more many functions which satisfy the necessary conditions of exisntence primitives , but the effective obtained of their can't obtained just using the integration of parts
2006-09-19 07:54:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
int(fg)=f int(g)+g int(f)
2006-09-19 07:50:57 · answer #4 · answered by Manolo 4 · 0⤊ 1⤋