a octagon will be made by cutting isosceles triangle from the corners of a square.
A.if AD=8,and AB=3,find the lengths of the sides of the octagon.
B.whats must the value of AB be so that the octagon has 8 sides of equal length?)Hint :assign the variable x to the distance AB.
2006-09-19 07:09:22 · 5 answers · asked by jouliette 1 in Science & Mathematics ➔ Mathematics
Cannot br solved unless points A, B, D are specified.
2006-09-19 07:27:29 · answer #1 · answered by psbhowmick 6 · 2⤊ 0⤋
A
4 sides = 8-3-3 = 2
4 sides = sqrt(3^2+3^2) = 3sqrt(2)
B
8-2x = sqrt(2x^2)
64-32x+4x^2 = 2x^2
x^2 - 32x +64 = 0
x = 8 + 4sqrt(2) or 8 - 4sqrt(2); since x cannot be larger than 8
x = 8-4sqrt(2)
2006-09-19 15:47:41 · answer #2 · answered by T 5 · 0⤊ 0⤋
add a diagram to your question. where are A and B found? are they vertices of sqaure or that of triangle or that of octagon? god you are confusing
2006-09-19 14:24:05 · answer #3 · answered by Farhali 2 · 0⤊ 0⤋
Data unclear
2006-09-19 14:16:53 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
I think this one need a diagram.
2006-09-19 14:15:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋