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ok, i have 2 questions, which out of 10 i cannot answer.
1] decribe the bonding arrangement in the benzene ring.
2]what role do delocalised electrons play in the bonding arrangement?
i really need help on these two questions, if you can help, much appreciated. thanks

2006-09-19 02:44:05 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

Benzene is an aromatic system. That means it has delocalized pi-electrons across the ring. The order of bond is somewhere between 1 and 2. That means that no bonds are single and no bonds are really double.

About the role of delocalized electrons...
Because of delocalized electrons all bonds are of the same length and the system is planar. Otherwise it would be 3D. Aromatic electrons play role in aromatic reactions: additions, substitutions etc.

2006-09-19 02:53:51 · answer #1 · answered by Anonymous · 0 0

1. perfectly hexagonal, aromatic, pi bonding

2. the single bonds (the bottom of the pi double bonds) are made from the electrons that are free to sorta "woosh" around the benzene ring causing the alternate single, double, single, double bonding of benzene that you draw. But in reality this "wooshing" of electrons swimming around the ring makes it more of a hybrid double/single bond which is why you sometimes see benzene with the dotted circle in the middle rather than the actual double/single bonds.

2006-09-19 09:56:32 · answer #2 · answered by ChemGeek 4 · 0 0

question 1
alternating double and single bonds...with a warning, these bonds can changes positions! Some chemists identify these as 1.5 bonds instead of double bonds and single bonds.
question 2
This explains the answer to question 1, the electrons move from 1 bonding position to another thus shifting the bonding structure causing the "hybrid" bonds

2006-09-19 09:56:16 · answer #3 · answered by The Cheminator 5 · 0 0

Sure thing, let me borrow your book.

2006-09-19 09:45:49 · answer #4 · answered by MoMattTexas 4 · 0 0

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