2006-09-19 01:15:45 · 5 answers · asked by Amit K 2 in Science & Mathematics ➔ Mathematics
Write R = N/D, with N = 30^65 - 29^65 and D = 30^64 + 29^64. Then
N = (30 - 29) * sum{i=0,...,64}(30^i * 29^(64-i))
= 30^64 + 29^64 + sum{i=1,...,63}(30^i * 29^(64-i)) > D.
Hence: R > 1.
2006-09-19 01:40:59 · answer #1 · answered by sabrina_at_tc 2 · 0⤊ 0⤋
Set it up a different way :
say R=( (A+1)^65 - A^65) / ((A+1)^64 + A^64)
where A=29.
You know what the expansions look like for the 64th and 65th powers from Pascal's Triangle and you don't want to do that much work so just look at the first few powers to see if you can find a general pattern with increasing power.
Best of Luck - Mike
2006-09-19 01:57:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
solve for R and see which condition satisfy the value of R
2006-09-19 01:29:31 · answer #3 · answered by Trans Atlantic 2 · 0⤊ 0⤋
use a calculator, by the way i think it's iii
2006-09-19 01:25:49 · answer #4 · answered by mellow~lisa 2 · 0⤊ 0⤋
dun really understand ur question! can u make it more clearer?
2006-09-19 01:19:42 · answer #5 · answered by chemistryppl 2 · 0⤊ 1⤋