The Area of square A is 10x the area of square B. What is the ratio of the perimeter of square A to the B.?

Answer 1

3.16227:1

Answer 2

A=a^2 B=b^2 A=10*B
a^2=10*b^2 a=squareroot(10)*b
Perimeter(A)/P(B)=4*a/4*b=
=a/b=sqrt(10)

Answer 3

Both of the above answers are right.

Let the first square have side 10, so area 100. Then the second square needs area 10, so side =SQUAREROOT(10).

Perimeter of first is 4*10=40. Perimeter of second is 4*SQUAREROOT(10).

Ratio of perimeters is 40/(4*SQUAREROOT(10)) = 10/SQUAREROOT(10)=3.16

Answer 4

hmm.. you let the side of sq A be a, and side of sq B be b..
therefore, a^2 = 10 * b^2 (since area is side squared)

(a^2/b^2) = 10

(a/b)^2 = 10
a/b = sq_root(10)

since perimeter is 4a and 4b for square a and b respectively,

their ratio, 4a/4b = a/b = sq_root(10)

so the answer is square root 10 : 1. (:

Answer 5

Try plugging in values for the length of sides of Square B.
Since it's a ratio, it will be the same no matter which you pick.