You already have the answer.
2006-09-19 00:29:24
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answer #1
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answered by astrokid 4
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129
2006-09-19 08:54:13
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answer #2
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answered by Kyrix 6
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60+19+x+y+z=208 and x+y+z=129
60+19+129=208
what's ur question?
2006-09-19 11:41:40
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answer #3
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answered by btribuwono 1
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if you want to find the value of X,Y and Z you can't solve it because you have 2 equation but if you want to find value of x+y+z of course it's will be 129..
:)
2006-09-19 09:58:59
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answer #4
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answered by insert 1
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x, y, z can equal any numbers as long as x+y+z=129 from your two equations above.
2006-09-19 07:30:17
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answer #5
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answered by zach_528 2
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We still need 3 seperate equations to solve for three unknowns.
2006-09-19 07:30:58
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answer #6
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answered by Anonymous
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x+y+z=129
You may want to look a little closer at the problem.
Type it here exactly as it appears in your book and you may be able to get some help.
2006-09-19 07:32:33
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answer #7
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answered by Anonymous
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something wrong in question -
www.afromneyafvf.com invites u as a math inspector . &gd 500
2006-09-19 07:46:59
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answer #8
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answered by tourist 3
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129
you already have the answer
2006-09-19 07:33:33
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answer #9
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answered by c2 brahmin 2
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