y+1/2=-1/3(x+1/2)?

Answer 1

y + 1/2 = -1/3(x+1/2)

By taking The LCM in the bracket of x + 1/2

y + 1/2 = -1/3[(2x+1)/2]

y + 1/2 = -1(2x + 1) / 6 .........[3*2=6]

Multiplying both sides by 6

6y + 3 = -1(2x + 1)

6y + 3 = -2x - 1

2x + 6y = -1 - 3

2x + 6y = -4

or

2x + 6y + 4 = 0

Answer 2

(2y + 1)/2 + 1/3(x+1/2)= 0
3(2y + 1) + 2(x + 1/2) = 0
6y + 3 + 2x + 1 = 0
6y + 2x + 4 = 0
3y + x + 2 = 0 or x + 3y + 2= 0

Answer 3

first open the brackets on right side.so that it will be
y+1/2=-1/3x-1/6 [as -1/3*1/2= -1/6]
now sent the fraction from left side to right
y= -1/3x -1/6-1/2
y= -1/3x -4/6 [as the LCM is 6]
y= -1/3x -2/3

Answer 4

y+1/2=-1/3(x+1/2) = p ( say)
Then the formula, (x, y) = ( -3*p -1/2, p - 1/2), will generate all possible pairs of values (x, y) corresponding to a given value of p.
The above formula is particularly useful to generate all possible rational solutions to the given equation.

It is needless to mention that:
x+3y = -2, is just another form of the given equation.

Answer 5

y = -1/3(x+1/2) - 1/2

y = -x/3 - 1/6 - 1/2

y = -x/3 - 2/3

Answer 6

assuming you mean

y + (1/2) = (-1/3)(x + (1/2))

y + (1/2) = (-1/3)x - (1/6)

multiply everythinb y 6

6y + 3 = -2x - 1
6y = -2x - 4
y = (-1/3)x - (2/3)

basically

((1/2),(1/2)), m = (-1/3)

This is in Point-Slope Form

Answer 7

y + 1/2 = -1/3(x+1/2)
y + 1/2 = -1/3[(2x+1)/2]
y + 1/2 = -1(2x + 1) / 6
6y + 3 = -1(2x + 1)
6y + 3 = -2x - 1
2x + 6y = -1 - 3
2x + 6y = -4
2x + 6y + 4 = 0

Answer 8

3y+3/2=-x+-1/2
=> 3y = -x -2
=> y = (-x -2)/3

Answer 9

y= -1/3x -1/2

Answer 10

x + 3y + 2 = 0

x = -3y - 2

&

y = (-1/3)x - (2/3)