Monochromatric light passes through a single slit,0.400 mm wide.It falls on a screen 1.6 m away.If the distance from the center of the pattern on the screen to the first band is 2.0 mm,what is the wavelength of the light?
2006-09-18 17:20:47 · 2 answers · asked by xxgodsgift2youxx 1 in Science & Mathematics ➔ Physics
The angle at which the dark bands occur is given by sin(theta)=mL/W. Where L = wavelength, W=slit width, and m=1,2,3... In your problem the slit is 4*10^-4 m wide and the angle is given by tan(theta)=(2*10^-3)/1.6. This means sin(theta) = 2*10^-3/sqrt(4*10^-6 + 1,6^2) For the first band, m=1 so
L = .4*10^-3 * 2*10^-3/sqrt(4*10^-6 + 1.6^2)
which comes out 5*10^-7m or 500nm
2006-09-18 18:01:40 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
this is a pretty simple problem
http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/sinslit.html
2006-09-19 00:39:16 · answer #2 · answered by abcdefghijk 4 · 0⤊ 0⤋