how about this one?

Question

find the components of the velocity of a car that is moving 60 km/h in a direction 70 degrees north of east.

Answer 1

First convert your 60 km/h into SI units:
60 km = 60,000 m
1 hr = 3600 s

60,000 m/3600 s = 16.667 m/s

Now, when a problem asks you to find the "components" of velocity, this means they want you to split up the vector into x and y components. Velocity is a vector, so your velocity in this case is 16.667 m/s in 70 degrees from the horizontal in the positive x-direction (just imagine your compass rose and create an angle 70 degrees above the east direction, which is in the positive x-direction).

And yay! Now you have a right triangle with an angle of 70 degrees and a hypotenuse of 16.667 m/s, your velocity. To find the components, just use your sin and cos functions.

sin 70 degrees = opposite/hypotenuse
cos 70 degrees = adjacent/hypotenuse

Your adjacent in this case is your x-component of velocity and your opposite is the y-component (draw your triangle if you're confused).

sin 70 degrees = opposite/16.667
(16.667 m/s)(sin 70) = opposite
15.662 m/s = opposite
Your y-component of velocity is 15.662 m/s upward (or, to the north).

cos 70 degrees = adjacent/16.667
(16.667 m/s)(cos 70) = adjacent
5.700 m/s = adjacent
Your x-component of velocity is 5.700 m/s rightward (or, to the east).

Good luck!

Answer 2

60 cos 70 km/h towards east
60 sin 70 km/h towards north.
Can you draw vectors?

Answer 3

420 @ 16m less the wind speed and humidity ratio