A pilot wants to fly a plane at 500 km/h directly north. the wind is blowing at 90 km/h from the east. Find the magnitude and direction of the course the pilot should fly.
2006-09-18 16:29:33 · 5 answers · asked by lorenzo p 1 in Science & Mathematics ➔ Physics
He will need to do 508 km/hr, and crab ten degrees east. When I learned to fly, I used to do these with a whiz-wheel (E6B circular slide rule/calculator). But I put away the whiz wheel years ago, and ran this on my HP-42S scientific calculator.
2006-09-18 16:36:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Draw a triangle with one leg equals 500 units pointing towards the north, and at right angle to it is another leg equal to 90 units pointing towards the east. Using Pythagorean theorem the magnitude you are after is the square root of the sum of the squares of 500 and 90, and the direction is equal to the angle whose tangent is 90/500 . Use a table to obtain that angle (say x) and indicate its direction as N x W.
I hope you can work out the actual numbers by yourself.
2006-09-18 17:15:45 · answer #2 · answered by tul b 3 · 0⤊ 0⤋
Magnitude: sqrt(500^2+90^2)=Approx 508.035 km/h
Bearing:taninverse (90/50)=Approx 11.337degs.
2006-09-18 16:38:02 · answer #3 · answered by Cheng J 2 · 0⤊ 0⤋
magnitude = approx 508 km/h
direction = approx 10 degrees NNE
2006-09-18 16:45:00 · answer #4 · answered by southeastside 2 · 0⤊ 0⤋
North -West
2006-09-18 16:32:15 · answer #5 · answered by Mechie 2 · 0⤊ 0⤋