Determine the last two digits in the number 20_ _ so that it is divisble by 2,3,5 and 9 write the number?

Answer 1

it is devisible by 5 so last digit = 0 or 5
it is divisible by 2 so last digit = even
from above 2 last digit 0
it is dvisible by 9 so sum of digit multiple of 9(auotmetically divisible by 3)

number = 20a0 a+2 = 9 so a = 7, a+2 has to be < 11 and multiple of 9
so number = 2070

Answer 2

since 2 and 5 are factors of the number you are looking for, so is 10 (because 2 * 5 is 10). This will make the last digit 0.
A number divisible by 9 has digits that add up to a number divisible by 9. 7 is the only digit you can put in the third spot that makes this true. Finally, any number divisible by 9 is divisible by 3. so the number is 2070

Answer 3

let's work it out so you know how to do the next one on your own. Any number divisible by 5 has to end in either 5 or 0. Any number divisible by 2 has to end in an even number, so the last number has to be 0. An interesting secret is that any number divisible by 3 will give you another number divisible by 3 when you add up all the digits (example 18: 1+8=9, 9 is divisible by 3 so 18 is divisible by 3). Using that rule, whatever number goes in the 3rd spot has to be able to add to 2 to make a number divisible by 3. Your options are 1 or 7. So the answer is either 2010 or 2070. Now pull out the calculator and divide these two numbers by 9. You will find that the only one divisible by 9 is 2070.

Hope that helps.

Answer 4

2070

The ones place digit has to be 0 because anything ending in 5 or 0 is divisible by 5, but something ending in 5 is not divisible by 2.

The tens place digits has to be 7 because 2070 is divisble by 9, no other number is. Anything divisible by 9 will also consequently be divisible by 3 because 3 is a factor of 9 so we do not even need to check to make sure it is divisible by 3.

Also I just realized something. Any number whose whole number components adds to 9 and have zeros in between is divisible by 9. For example. 20304 is divisible by 9 because 2+3+4 = 9 Just replace the zeros with plus to check.

Lets try another:

801 / 9 = 89
40204 / 9 = 4467
1020303 = 113367
10101010101010101 / 9= 1122334455667789

Actually this works without the zeros too.

Answer 5

number must be divisble by 2, 5, & 9 (since it is divisible by 9, it must be divisible by 3)

2*5*9 = 90

the number is 20?? or 2000 + n, where 0 < n < 100

we know that (2000+n)/90 = m, where m is an integer

2000/90 + n/90 = m
22 + 20/90 + n/90 = m
20/90 + n/90 = m - 22 = p, an integer, minimum = 1
20/90 + n/90 = 1
20+n = 90

therefore n = 70.

Answer 6

2070. Since 3 is a factor of 9, the factors you have to work wiht are 2, 3, 3, 5. Multiplying these together gives 90, so the result just has to divide by 90. 1800 obviously divides by 90, so that means 1980 does, and add another 90 for 2070. You can check it on a calculator if you like.

Answer 7

Which quantity does 2 bypass into? Even or unusual? 3- Any quantity that provides as much as 3 is divisible by using 3 -15 = a million+5, divisible by using 3 5- could bring about 5 or 0 precise? 9 What comes after 999? 10 Even or unusual?

Answer 8

the last 2 digits are 70

Answer 9

90

Answer 10

the number is 2070