- of $56, & the practice time will cost $7.50 per hour. Which inequality should julie use to determine the maxium # of hours, h, she can practice w/o spending more than $300??
Im confused because i dont see how id figure it out without an amount of hours.
I thought the answer was 42 + 56 + 7.50h < or = to 300... what does everyone else think about it?
2006-09-18 16:00:17 · 11 answers · asked by crazybrunette1991 2 in Science & Mathematics ➔ Mathematics
or would the inequality 7.50h-42-56< or = to 300 work?????
2006-09-18 16:25:22 · update #1
Some of you arent helping. Or couldnt it be 56 + 7.50h < 300 ......???
2006-09-18 17:03:04 · update #2
assuming she only takes one lesson
42 + 56 + 7.5h <= 300
7.5h + 98 <= 300
7.5h <= 202
h <= 26 hours and 56 minutes
if she takes more than one lesson, then
7.5x + 56y + 42 <= 300
or
7.5x + 56y <= 258
2006-09-18 17:42:25 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
42 + 56 *7.50h < 300 You're right, you just need to figure out h.
You just need to treat the < as an = sign and use algebra
Collect like terms on the left
42+56 = 98
98 * 7.50h < 300 Subtract 98
7.50h < 202
Than divide by 7.50
h < 26.93333! Rounded to 27 hours. There ya go
2006-09-18 23:04:27 · answer #2 · answered by Eric 2 · 0⤊ 0⤋
You have to solve for h. You starting inequality is fine. Just finish so that you have:
h < or = to ??
(hint: add 42+56 and then subtract that sum from both sides of the inequality. Next divide both sides by 7.5 to get your answer for "h".
2006-09-18 23:05:25 · answer #3 · answered by IMHO 3 · 0⤊ 0⤋
$300 - $42 - $56 = $202 -- That's how much is left over for practice.
$202 / $7.5 = 26.9 hours of practice time.
2006-09-18 23:07:01 · answer #4 · answered by johntadams3 5 · 1⤊ 0⤋
(42 + 56) + (h * 7.50) = 300
(98) + (h * 7.50) = 300
-98 -98 on each side
h * 7.50 = 202
divide each side by 7.50
h = 26.93
2006-09-18 23:16:11 · answer #5 · answered by ulikemyuser 1 · 0⤊ 0⤋
56+42=98.00 300-98=202
7.50 diveded by 202 and you will have your answer
2006-09-18 23:05:11 · answer #6 · answered by Kimmy 3 · 1⤊ 0⤋
add you 42+56=98
98-300=202
202/7.50 = 26.933333 hr of pratice
2006-09-18 23:05:53 · answer #7 · answered by luv2wubsy 3 · 1⤊ 0⤋
You're right so far
So 98 + 7.50h <=300
which simplifies to 7.50h <= 202
Divide both sides by 7.50 to get h
2006-09-18 23:06:30 · answer #8 · answered by banjuja58 4 · 1⤊ 0⤋
yeap, i think the inequality you wrote is just fine. you'll get 26.93 hours for that.
so julie's maximum hours to spend not more than $300 on ice skating is 26.93 hours.
2006-09-18 23:31:21 · answer #9 · answered by mowslotion 1 · 0⤊ 0⤋
she can practice 26 times
2006-09-18 23:04:46 · answer #10 · answered by PAUL F 3 · 0⤊ 0⤋