2006-09-18 15:55:25 · 8 answers · asked by june_ellis86 1 in Education & Reference ➔ Homework Help
Add 49 to both sides to get x^2=49, then do the sq rt of both sides to get x = plus or minus 7.
2006-09-18 15:58:05 · answer #1 · answered by hayharbr 7 · 0⤊ 1⤋
Well, subtract 49 from both sides and then find all the possible square roots of 49. They turn out to be positive and negative seven, so x would be positive and negative seven. Unfortunately, you cannot solve by completing the square on this question because there is no bx value in the quadratic equation; therefore, (-b/2a)^2, which would normally be the c value, would be zero.
2006-09-18 16:05:20 · answer #2 · answered by l;wksjf;aslkd 3 · 1⤊ 1⤋
X^2 – 49 = 0
X^2 = 49
X = Square Root of 49
X = 7
2006-09-18 16:41:21 · answer #3 · answered by Anonymous · 2⤊ 0⤋
x=7
2006-09-18 15:58:19 · answer #4 · answered by PAUL F 3 · 0⤊ 2⤋
Solve it like any other.
x^2 - 49 = 0
x^2 = 49
Take the square root of both sides and you get 7.
2006-09-18 15:58:36 · answer #5 · answered by Joelle 1 · 1⤊ 1⤋
Sorry I can't remember exactly how to get to the second step but you must remember both negative and positive otherwise you're only going to be half right.
x^2 - 49 = (x - 7)(x + 7)
For that to equal 0 then one of the brackets must equal 0
Therefore x = 7, or x = -7.
2006-09-18 16:08:11 · answer #6 · answered by Anonymous · 0⤊ 1⤋
X squared - 49 = 0
(X - 7) (X + 7) = 0
Answers:
X = -7
and
X = 7
2006-09-18 16:05:00 · answer #7 · answered by zahbudar 6 · 0⤊ 1⤋
Take the square root of all parts:
x - 7 = 0
Simplify:
x = 7
2006-09-18 16:03:22 · answer #8 · answered by *AstrosChick* 5 · 0⤊ 1⤋