Please, can someone show me howto do this.
2006-09-18 15:51:55 · 7 answers · asked by TehEagle 1 in Science & Mathematics ➔ Mathematics
the answer is 2x-y=-9
2006-09-18 16:30:37 · update #1
Slope> -5/2
eqn is of the form y=(-5/2)x+k
or 2y+5x=2k.
Since (-2,5) Satisfies the eqn, k=0.
Eqn of the line is 5x+2y=0
2006-09-18 16:01:08 · answer #1 · answered by astrokid 4 · 0⤊ 0⤋
First, find the slope of the line containing the two given points. Remember this is done by:
(y1 - y2)/(x1 - x2) <---note that you can also use (y2 - y1)/(x2 - x1) for the same value.
Once you have that slope, which is - 5/2, recall that parallel lines always have the same slope, so if you want the equation of the line parallel to the one given, it also must have a slope of - 5/2.
Use the form y = mx + b to find this new equation. m = slope of the line (same as the one given), and b = the y-intercept of the line...that is, where the line intersects the y-axis. To figure out the equation of your new line, take
y = mx + b <------ m = -5/2
y = (- 5/2)x + b <------Now, solve for b
Plug in the x and y values of the given point (-2, 5)
y = 5, x = -2
5 = (-5/2)(-2) + b
5 = 5 + b
Thus, b = 0.
Now go back to the equation of your line, y = mx + b. Now you have the constant values of m and b, and you have your equation:
y = (-5/2)x
since b = 0.
Good luck, hope you understand it!
2006-09-18 16:02:37 · answer #2 · answered by Dumblydore 3 · 0⤊ 0⤋
Find the slope of the parallel line using the two given points.
Parallel lines have the same slope so this gives you the slope of the line you are looking for too.
Then use the slope and point to find your equation
2006-09-18 16:01:52 · answer #3 · answered by Demiurge42 7 · 0⤊ 0⤋
Since both lines have the same slope,
(y-5)/(x+2) = (6-1)/(1-3)
-2(y-5) = 5(x+2)
2y+5x=0
2006-09-18 16:04:38 · answer #4 · answered by ctyuang 1 · 0⤊ 0⤋
(1,6) and (3,1)
m = (1 - 6)/(3 - 1)
m = (-5)/2
m = (-5/2)
(-2,5), m = (-5/2)
5 = (-5/2)(-2) + b
5 = 5 + b
b = 0
ANS : y = (-5/2)x
in standard form
2y = -5x
5x + 2y = 0
2006-09-18 17:44:21 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
Find the slope of the two points.
.........6 - 1 ..........5
m = ----------- = ---------
.........1 - 3 .........-2
m = -5/2
Now, use the form y = mx +b.
5 = (-5/2)*-2 + b
b = 0
So
y = (-5/2)x
2006-09-18 16:03:26 · answer #6 · answered by something 3 · 0⤊ 0⤋
Parallel lines have the same slope.
Since you have you have two points, use your
y2-y1
--------- = m
x2-x1
I hope this helps!
2006-09-18 16:01:55 · answer #7 · answered by Trish 2 · 0⤊ 0⤋