Given f(x) = –x3 + 2x2 – 2x – 2, find f(–2) and f(0).?

Answer 1

to find f(-2), plug in -2 for every x in the equation, so you get (-2)^3+2(-2)^2-2(-2)-2. Then solving it you get, -8+8+4-2=2.

to find f(0), you do the same thing, and you end up with -2.

good luck!

Answer 2

f(-2) = -(-2)3 - 2(-2)2 + 2(-2) +a million f(-2) = 6+8+-4+a million f(-2) = 11 f(0) = -(0)3-2(0)2+2(0)+a million f(0) = 0+0+0+a million f(0)=a million f(2) = -(2)3-2(2)2+2(2)+a million f(2)= -6 - 8+4+a million f(2) = 9 no longer probably specific bout all that yet i gave it a shot! Been a mutually as considering I had a math type!

Answer 3

f(x) = –x^3 + 2x^2 – 2x – 2
If f(-2), then:
f(-2) = -3(-2^3) + 2(-2^2) – 2 (-2) – 2
f(-2) = -3(-8) + 2(4) – 2(-2) -2
f(-2) = +24 +8 +4 -2
f(-2) = +36 -2
f(-2) = +34

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f(x) = –x^3 + 2x^2 – 2x – 2

If f(0), then:
f(0) = -3(0^3) + 2(0^2) – 2 (0) – 2
f(0) = - 0 + 0 – 0 -2
f(0) = -2

Answer 4

f(-2)=2, f(0) =-2

Answer 5

Just substitute -2 for x for your first answer. Then substitute the 0 for x for your second answer.

f(x) = 18 and -2.

Answer 6

f(-2)= 18, f(0)= -2
just "plug" -2, and 0 into x
mulan2890 forgot the - sign at the beginning

Answer 7

f(-2) = 4
f(o) = -2

if 2x2 means two times x squared.