hi i am having trouble with this question
Write the equation of a circle centred at the origin with radius 1 in polar form (in its simplest form).
any help would be gratefully appreciated
2006-09-18 15:46:50 · 6 answers · asked by zz06 3 in Science & Mathematics ➔ Mathematics
Use the variable r for r and either theta (spelt in full) or the abbreviation t for q.
2006-09-18 15:59:48 · update #1
q should say theta
2006-09-18 16:00:09 · update #2
Answer r=1.
Why? Because if you take all the points whose distance (r) from the origin is equal to 1, then what you get is a circle with center at the origin and radius 1.
2006-09-18 15:53:34 · answer #1 · answered by firat c 4 · 1⤊ 1⤋
The equation of the circle with center at origin and radius is
x^2 +y^2 = r^2
Here put x = rcos A and y =r sin A then equation in polar form will be (r cos A)+(r sinA)^2 = r^2
but r=1 given then
cos^A + sin^2 A =1 is the required equation
2006-09-18 22:57:05 · answer #2 · answered by Amar Soni 7 · 0⤊ 1⤋
Your circle has radius 1 and is centered on the origin, so the polar-coordinate equation is r = 1.
2006-09-18 23:38:25 · answer #3 · answered by alnitaka 4 · 0⤊ 0⤋
The cartesian equation (in terms of x and y) of a circle as you describe is:
x^2 + y^2 = 1
The general rule for an equation of a circle is:
(x + a)^2 + (y + b)^2 = r^2
where a and b are the x and y coordinates respectively of the centre of the circle and r is the radius.
2006-09-18 22:55:10 · answer #4 · answered by Anonymous · 0⤊ 1⤋
It's just r=1.
2006-09-18 22:54:07 · answer #5 · answered by hayharbr 7 · 1⤊ 1⤋
x^2 + y^2 = 1
r(theta) = 1
2006-09-18 22:59:45 · answer #6 · answered by ali 6 · 0⤊ 1⤋