does the number .0558 have three significant figures of four signifigant figures?
2006-09-18 15:35:29 · 14 answers · asked by Simply Me 5 in Science & Mathematics ➔ Mathematics
Three, because it's written 5.58x10^-2.
2006-09-18 15:39:10 · answer #1 · answered by nyad13 2 · 3⤊ 0⤋
4
2006-09-18 22:39:03 · answer #2 · answered by jaemin 1 · 0⤊ 3⤋
4
2006-09-18 22:36:59 · answer #3 · answered by Hello!!!! 3 · 0⤊ 3⤋
4
2006-09-18 22:36:54 · answer #4 · answered by jperk1941 4 · 0⤊ 3⤋
Significant figures are the number of digits in a number, starting from the first non-zero digit and including final zeros (eg .0012340 has 5 significant figures).
So in your case, there are three.
2006-09-18 23:56:26 · answer #5 · answered by Retro Deviant 2 · 2⤊ 0⤋
Four. Going to the right of the decimal place (._____), the first place represents the tenth spot. Then the second place represents the hundredths place, then thousandths, and so on.
For example: .12345, the 1 is in the tenths place, 2 is the hundredths place, and so on.
Since 0 is a numerical integer, it has significant value in the tenths place. It states that the tenths value in your given number is 0.
=)
2006-09-18 22:40:53 · answer #6 · answered by Anonymous · 0⤊ 3⤋
4 figures
2006-09-18 22:39:48 · answer #7 · answered by tingerpoo 2 · 0⤊ 3⤋
How can anyone answer 4? It is obviously only 3 sig figures.
2006-09-18 22:42:30 · answer #8 · answered by ali 6 · 2⤊ 1⤋
It has 3. The '0' doesn't count. It is actually
5.58x10^-2.
2006-09-18 22:39:49 · answer #9 · answered by Helzabet 6 · 3⤊ 0⤋
3
the zeros before 558 does not count because it only designate the magnitude of the number.
2006-09-18 22:51:48 · answer #10 · answered by Anonymous · 3⤊ 0⤋