-3-4(t-5)=-2(t+3)+11?

Question

can you explain how to get to the answer please.

Answer 1

-3 - 4(t - 5) = -2(t + 3) + 11
-4(t - 5) = -2(t + 3) + 14
-4(t - 5) = -2((t + 3) - 7)
2(t - 5) = (t + 3) - 7
2t - 10 = t + 3 - 7
2t - 10 = t - 4
t = 6

Answer 2

-3-4(t-5)=-2(t+3)+11 multipy parenthesis to get:
-3-4t+20=-2t-6+11 add 4t to both sides and simplify numbers:
17=2t+5 subtract 5 from both sides:
12=2t divide both sides by 2:
6=t

then plug it into the equation to verify

Just remember that you can do anything you want to an equation, as long as you do the same thing to both sides.

Answer 3

T=6!!!!!

Answer 4

-3-4(t-5)=-2(t+3)+11 (Firstly expand your equation and you get the following)
-3-4t+20 = 2t + 6 + 11 (Now simplify your equation and you get the following)
17 - 4t = 2t + 17 (Now shift the t to one side and you get the following)
-4t - 2t = 17 - 17 (Now simplify your equation and you get the following)
-6t = 0
t =0


Thats your answer.

Cheers