can x to the 3rd + 27 be reduced or factored?

Question

i know that 27 can change to 3 to the 3rd.

Answer 1

yes u can reduce it this is how:
follow this format:
x^3 + a^3=(x+a)(x^2-ax+a^2)

this would mean that in your case, x=x and a=3

substitute the numbers in forming
(x+3)(x^2 -3x +9)

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Answer 2

Yes, it can be factored.

I generally look at the power and see if the number term is really another number to that power. and 27 is 3^3. So I know to pull out (x + 3) [since we're dealing with addition everywhere.]

I divide (x+3) into x^3 + 27, to get...

(x + 3) ( x^2 - 3x + 9)


There's NO need to remember a long complex formula. There are neat results in Calculus II from the idea of dividing by a factor. Ask me if you have any questions about any of this!

Answer 3

x^3 + 27 = (x + 3)(x^2 - 3x + 9)

just take the cbrt of 27 which is 3

Answer 4

yes it can be factored. The sum of cubes law. There is also the difference of cubes.
Sum of cube law is a^3+b^3 = (a+b)(a^2-ab+b^2)
Difference of cubes is a^3-a^3 = (a-b)(a^2+ab+b^2)
So the answer to your question is it can be factored into (x+3)(x^2+3x+9).

Answer 5

yes

Answer 6

factored