4x+3y=-15
2006-09-18 13:26:56 · 9 answers · asked by Emilia r 1 in Science & Mathematics ➔ Mathematics
you can't solve for both x and y without another equation. If you're trying to solve for "y" you move around the variables.
4x+3y = -15 (subtract 4x from both sides)
3y = -15 - 4x (divide by 3 on both sides)
y = -5 - 4/3 x
y = -4/3 x - 5 (y = mx + b form)
2006-09-18 13:34:51 · answer #1 · answered by leon27607 3 · 0⤊ 0⤋
first thing you do is solve for x by subtracting 4x from both sides giving you 3y=-4x-15 then you divid eboth sides by 3 giving you y=-(4/3)x-5 if you are trying to make a graph stop here. if not continue reading. then plug this equation into the original in place of y giving you 4x+3(-(4/3)x-5)=15 then solve for x. plug this new equation in for x and solve for y CONGRADULATIONS!!! you have just found a point in space.
2006-09-18 20:53:08 · answer #2 · answered by Sniper 4 · 0⤊ 0⤋
4x+3y=15
subtract 4 from 4 and 15, then divide the 15 by 3 and get your answer. (3.6)
i believe this is correct
2006-09-18 20:54:42 · answer #3 · answered by nesha 1 · 0⤊ 0⤋
y=-1 x=-3
2006-09-18 20:30:34 · answer #4 · answered by Phish 2 · 0⤊ 0⤋
This is a two variable equation (x,y),so if you want to find the value of each variable you must have a second equation with also the same variables (x,y) ,or at least finding the value of one of the two variable then applying it in the equation to find the other .Now you cant solve it .
2006-09-18 20:39:36 · answer #5 · answered by vivgig2001 2 · 0⤊ 0⤋
4x+3y=-15
7xy=-15
7xy+15=22xy
Hope this helps!!!
2006-09-18 20:34:41 · answer #6 · answered by Ali.D 4 · 0⤊ 0⤋
The answer is the line y = -(4/3)x - 5.
2006-09-18 20:34:19 · answer #7 · answered by eyanyo13 3 · 0⤊ 0⤋
Substituting x = 3p, we obtain:
y = -(4p+5)
So, x=3p; y= -(4p+5), generates all possible solutions to the given equation for any given value of p.
The above formula is particularly useful when determining all possible rational solutions ( including integer solutions) to the given equation.
2006-09-19 04:46:59 · answer #8 · answered by K Sengupta 4 · 0⤊ 0⤋
What are you trying to do, make a graph?
2006-09-18 20:28:54 · answer #9 · answered by bruinfan 7 · 0⤊ 0⤋