find the derivative of the function f(x)=(8x^2+x)^7?

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2006-09-18 13:25:36 · 3 answers · asked by jilljeter2004 1 in Science & Mathematics ➔ Mathematics

Use the Chain Rule: let u = 8x^2 + x; du/dx = 16x+1

y = u^7; dy/du = 7u^6

dy/dx = dy/du x du/dx = 7u^6 (16x+1) = 7(8x^2+x)(16x+1)

2006-09-18 13:29:52 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋

f'(x) = [7(8x^2 + x)^6] (16x +1)

2006-09-18 13:30:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋

7*(8x^2+x)^6*(16x+1)

2006-09-18 13:29:42 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋