11. -2x= -4x+20 i subtracted -2x from both sides and got 0=-6x+20 then i dont know what to do next please help
2006-09-18 12:43:02 · 11 answers · asked by lilangel93 1 in Education & Reference ➔ Homework Help
-2x= -4x+20
4x-2x=20
2x=20
x=10
2006-09-18 12:48:56 · answer #1 · answered by energywire 1 · 0⤊ 0⤋
Add 4x to both sides of the equation to get your unknowns on the
left side of the equation and have your known by itself on the right. The equation is now 2x = 20. Divide both sides of the equation by 2. x = 10. To check, substitute 10 for x in the original equation. -2(10) = -4(10)+ 20. -20= -20. The solution, 10 is correct.
2006-09-18 20:19:26 · answer #2 · answered by Max 6 · 0⤊ 0⤋
You have to get both the knowns and unknowns on the same side of the equal sign. When you move them from one side to the other you switch their signs.
11 - 2x = -4x + 20
-2x + 4x = 20 - 11
2x = 9
x = 4.5
2006-09-18 19:48:46 · answer #3 · answered by j H 6 · 0⤊ 0⤋
-2x = -4x + 20 (original)
2x = 20 (added 4x to both sides)
x = 10 (divided both sides by 2)
2006-09-18 19:47:14 · answer #4 · answered by loveholio 5 · 0⤊ 0⤋
-2x = -4x+ 20
4x-2x= 20 (add 4x to each side)
2x= 20
x= 10
2006-09-18 19:48:46 · answer #5 · answered by sima p 1 · 0⤊ 0⤋
yes, but subtracting -2x from each side is the same as adding 2x to each side, right?
so, 0 = -2x +20
now, rearrange by adding 2x to both sides again
2x = 20
now divide by 2
x = 10
2006-09-18 19:47:58 · answer #6 · answered by t_e_sumner 3 · 0⤊ 0⤋
Start over. -2x=-4x+20, Add 4x to each side, it will be easier for you.
2006-09-18 19:45:14 · answer #7 · answered by princess consuela banana hammock 2 · 0⤊ 0⤋
EHHH iM DOiNG THiS TOO
Algerbra? hehe
well if theres not a number on the other
side thats a number alone you dont use that
so add 4 on both sides.
2x=20
then...
divide 2 by both sides.
then [[x =10]]
:D
2006-09-18 19:52:25 · answer #8 · answered by Cindyyy<3 4 · 0⤊ 0⤋
-2x= -4x+20
2x(-2x)= 2x-4x +20
0=-2x +20
x=10
2006-09-18 19:55:43 · answer #9 · answered by monet r 2 · 0⤊ 0⤋
since you have gotten 2 different answers here try going to the website math.com. they have tutors and homework help on this website.
2006-09-18 19:56:53 · answer #10 · answered by kimber1731 2 · 0⤊ 0⤋