A general rule for those climbing more than 7000 feet above sea level is to allow a total of (a - 7000/2000 + 2) weeks of camping during the ascension. In this expression, "a" represents the altitude in feet. If a group of mountain climbers have allowed for 9 weeks of camping in their schedule, how high can the climb without worrying about altitude sickness?
2006-09-18 11:24:45 · 3 answers · asked by mariah_fennell 1 in Education & Reference ➔ Homework Help
you forgot the brackets for (a-7000) and all the people are confused - lol.
(a-7000)/2000 +2 = 9
a = (9-2)*2000 + 7000 = 21000 feet
2006-09-18 11:40:41 · answer #1 · answered by aeroman762002 5 · 0⤊ 0⤋
Ok, so first clearly write out your equation:
number_of_weeks_camping = (a - 7/2 + 2)
We know that the number of camping weeks = 9
So:
9 = (a - 7/2 + 2)
And we solve for "a" to get the altitude at which they can safely climb. You're in algebra... solve it.
It seems the number you get when solving for "a" is really low. Are you sure you copied the equation correctly?
2006-09-18 18:32:26 · answer #2 · answered by Ubi 5 · 0⤊ 0⤋
9=(a-7/2+2) -> 9=a-3/2 -> 9+3/2 = a -> a = 21/2 :)
problems like this are usually very easy to solve... try to concentrate more on the statement of the problem so u can realize what is it that u are asked....
once u manage that u're almost finished
2006-09-18 18:42:34 · answer #3 · answered by dmarius1 2 · 0⤊ 0⤋